Integrand size = 20, antiderivative size = 82 \[ \int \frac {A+B x}{(a+b x) (d+e x)^2} \, dx=-\frac {B d-A e}{e (b d-a e) (d+e x)}+\frac {(A b-a B) \log (a+b x)}{(b d-a e)^2}-\frac {(A b-a B) \log (d+e x)}{(b d-a e)^2} \]
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Time = 0.05 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {78} \[ \int \frac {A+B x}{(a+b x) (d+e x)^2} \, dx=-\frac {B d-A e}{e (d+e x) (b d-a e)}+\frac {(A b-a B) \log (a+b x)}{(b d-a e)^2}-\frac {(A b-a B) \log (d+e x)}{(b d-a e)^2} \]
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Rule 78
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {b (A b-a B)}{(b d-a e)^2 (a+b x)}+\frac {B d-A e}{(b d-a e) (d+e x)^2}+\frac {(-A b+a B) e}{(b d-a e)^2 (d+e x)}\right ) \, dx \\ & = -\frac {B d-A e}{e (b d-a e) (d+e x)}+\frac {(A b-a B) \log (a+b x)}{(b d-a e)^2}-\frac {(A b-a B) \log (d+e x)}{(b d-a e)^2} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.98 \[ \int \frac {A+B x}{(a+b x) (d+e x)^2} \, dx=\frac {B d-A e}{e (-b d+a e) (d+e x)}+\frac {(A b-a B) \log (a+b x)}{(b d-a e)^2}+\frac {(-A b+a B) \log (d+e x)}{(b d-a e)^2} \]
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Time = 2.18 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.01
method | result | size |
default | \(\frac {\left (A b -B a \right ) \ln \left (b x +a \right )}{\left (a e -b d \right )^{2}}-\frac {A e -B d}{\left (a e -b d \right ) e \left (e x +d \right )}-\frac {\left (A b -B a \right ) \ln \left (e x +d \right )}{\left (a e -b d \right )^{2}}\) | \(83\) |
norman | \(\frac {\left (A e -B d \right ) x}{d \left (a e -b d \right ) \left (e x +d \right )}+\frac {\left (A b -B a \right ) \ln \left (b x +a \right )}{a^{2} e^{2}-2 a b d e +b^{2} d^{2}}-\frac {\left (A b -B a \right ) \ln \left (e x +d \right )}{a^{2} e^{2}-2 a b d e +b^{2} d^{2}}\) | \(109\) |
parallelrisch | \(\frac {A \ln \left (b x +a \right ) x b \,e^{2}-A \ln \left (e x +d \right ) x b \,e^{2}-B \ln \left (b x +a \right ) x a \,e^{2}+B \ln \left (e x +d \right ) x a \,e^{2}+A \ln \left (b x +a \right ) b d e -A \ln \left (e x +d \right ) b d e -B \ln \left (b x +a \right ) a d e +B \ln \left (e x +d \right ) a d e -A a \,e^{2}+A b d e +B a d e -b B \,d^{2}}{\left (a^{2} e^{2}-2 a b d e +b^{2} d^{2}\right ) \left (e x +d \right ) e}\) | \(160\) |
risch | \(-\frac {A}{\left (a e -b d \right ) \left (e x +d \right )}+\frac {B d}{\left (a e -b d \right ) e \left (e x +d \right )}+\frac {\ln \left (-b x -a \right ) A b}{a^{2} e^{2}-2 a b d e +b^{2} d^{2}}-\frac {\ln \left (-b x -a \right ) B a}{a^{2} e^{2}-2 a b d e +b^{2} d^{2}}-\frac {\ln \left (e x +d \right ) A b}{a^{2} e^{2}-2 a b d e +b^{2} d^{2}}+\frac {\ln \left (e x +d \right ) B a}{a^{2} e^{2}-2 a b d e +b^{2} d^{2}}\) | \(181\) |
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Time = 0.23 (sec) , antiderivative size = 148, normalized size of antiderivative = 1.80 \[ \int \frac {A+B x}{(a+b x) (d+e x)^2} \, dx=-\frac {B b d^{2} + A a e^{2} - {\left (B a + A b\right )} d e + {\left ({\left (B a - A b\right )} e^{2} x + {\left (B a - A b\right )} d e\right )} \log \left (b x + a\right ) - {\left ({\left (B a - A b\right )} e^{2} x + {\left (B a - A b\right )} d e\right )} \log \left (e x + d\right )}{b^{2} d^{3} e - 2 \, a b d^{2} e^{2} + a^{2} d e^{3} + {\left (b^{2} d^{2} e^{2} - 2 \, a b d e^{3} + a^{2} e^{4}\right )} x} \]
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Leaf count of result is larger than twice the leaf count of optimal. 355 vs. \(2 (63) = 126\).
Time = 0.71 (sec) , antiderivative size = 355, normalized size of antiderivative = 4.33 \[ \int \frac {A+B x}{(a+b x) (d+e x)^2} \, dx=\frac {\left (- A b + B a\right ) \log {\left (x + \frac {- A a b e - A b^{2} d + B a^{2} e + B a b d - \frac {a^{3} e^{3} \left (- A b + B a\right )}{\left (a e - b d\right )^{2}} + \frac {3 a^{2} b d e^{2} \left (- A b + B a\right )}{\left (a e - b d\right )^{2}} - \frac {3 a b^{2} d^{2} e \left (- A b + B a\right )}{\left (a e - b d\right )^{2}} + \frac {b^{3} d^{3} \left (- A b + B a\right )}{\left (a e - b d\right )^{2}}}{- 2 A b^{2} e + 2 B a b e} \right )}}{\left (a e - b d\right )^{2}} - \frac {\left (- A b + B a\right ) \log {\left (x + \frac {- A a b e - A b^{2} d + B a^{2} e + B a b d + \frac {a^{3} e^{3} \left (- A b + B a\right )}{\left (a e - b d\right )^{2}} - \frac {3 a^{2} b d e^{2} \left (- A b + B a\right )}{\left (a e - b d\right )^{2}} + \frac {3 a b^{2} d^{2} e \left (- A b + B a\right )}{\left (a e - b d\right )^{2}} - \frac {b^{3} d^{3} \left (- A b + B a\right )}{\left (a e - b d\right )^{2}}}{- 2 A b^{2} e + 2 B a b e} \right )}}{\left (a e - b d\right )^{2}} + \frac {- A e + B d}{a d e^{2} - b d^{2} e + x \left (a e^{3} - b d e^{2}\right )} \]
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Time = 0.21 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.45 \[ \int \frac {A+B x}{(a+b x) (d+e x)^2} \, dx=-\frac {{\left (B a - A b\right )} \log \left (b x + a\right )}{b^{2} d^{2} - 2 \, a b d e + a^{2} e^{2}} + \frac {{\left (B a - A b\right )} \log \left (e x + d\right )}{b^{2} d^{2} - 2 \, a b d e + a^{2} e^{2}} - \frac {B d - A e}{b d^{2} e - a d e^{2} + {\left (b d e^{2} - a e^{3}\right )} x} \]
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Time = 0.30 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.23 \[ \int \frac {A+B x}{(a+b x) (d+e x)^2} \, dx=-\frac {{\left (B a e - A b e\right )} \log \left ({\left | b - \frac {b d}{e x + d} + \frac {a e}{e x + d} \right |}\right )}{b^{2} d^{2} e - 2 \, a b d e^{2} + a^{2} e^{3}} - \frac {\frac {B d}{e x + d} - \frac {A e}{e x + d}}{b d e - a e^{2}} \]
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Time = 1.26 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.16 \[ \int \frac {A+B x}{(a+b x) (d+e x)^2} \, dx=\frac {2\,\mathrm {atanh}\left (\frac {a^2\,e^2-b^2\,d^2}{{\left (a\,e-b\,d\right )}^2}+\frac {2\,b\,e\,x}{a\,e-b\,d}\right )\,\left (A\,b-B\,a\right )}{{\left (a\,e-b\,d\right )}^2}-\frac {A\,e-B\,d}{e\,\left (a\,e-b\,d\right )\,\left (d+e\,x\right )} \]
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